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7b^2+22b-24=0
a = 7; b = 22; c = -24;
Δ = b2-4ac
Δ = 222-4·7·(-24)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-34}{2*7}=\frac{-56}{14} =-4 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+34}{2*7}=\frac{12}{14} =6/7 $
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